(I) ABAC : DEF = GB - + * (II) HEGF - HBID = HED ---------------------- (III) EKBI - HKGI = ICDC (IV) (V) (VI) Solution: (III.1) C = 0 (I.1) B * F == 0 (VI.1) B * D == 0 Therefore B = 5 and D, F are even. (II.1) F == 2D (V.1) I == 3D (III.4) E = H + I (III.2) 5 = G + D (I) D * G <= A (IV.2) A = G + B + 1 = G + 6 no carry as G < A 9590 : 274 = 35 - + * 1734 - 1562 = 172 ---------------------- 7856 - 1836 = 6020 References: Hoer Zu, No 45, 2002