S I X + S I X + S I X = N I N E + N I N E Solution: This one is simple case checking. First NINE < 1500. So N=1 and 0<=I<4. N I NIN 2/3 NIN 1 0 101 67.333 1 1 111 74.000 1 2 121 80.666 1 3 131 87.333 1 4 141 94.000 We see that only I=4 gives possible I for SIX. As 3 | NINE we have to try 1410, 1413, 1416, 1419 to check. These give 940, 942, 944, 946. Only E=3 gives a valid solution. 942 + 942 + 942 = 1413 + 1413 References: - Author: Alan Wayne - Martin Gardner; Sci. Am. (Sep. 1975) - Martin Gardner; The Magic Numbers of Dr. Matrix, 1985 Chap. 18: The King James Bible